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0=1.5x^2-52.5x-4500
We move all terms to the left:
0-(1.5x^2-52.5x-4500)=0
We add all the numbers together, and all the variables
-(1.5x^2-52.5x-4500)=0
We get rid of parentheses
-1.5x^2+52.5x+4500=0
a = -1.5; b = 52.5; c = +4500;
Δ = b2-4ac
Δ = 52.52-4·(-1.5)·4500
Δ = 29756.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52.5)-\sqrt{29756.25}}{2*-1.5}=\frac{-52.5-\sqrt{29756.25}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52.5)+\sqrt{29756.25}}{2*-1.5}=\frac{-52.5+\sqrt{29756.25}}{-3} $
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